The ____ are the initial branches of the trachea that lead into each lung
a. bronchioles
b. alveoli
c. pleura
d. bronchi
e. larynx
D
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Salt is often used to melt ice on roads during the winter because it lowers the freezing/melting point of water. When salt dissolves in water, individual Na+ and Cl- ions break away from the salt lattice and become surrounded by water molecules. Why would this cause ice to melt?
A. Hydrogen bonds are broken, and the salt ions interfere with interactions between H and O. As a result, it is more difficult for water molecules to bond and form ice. B. Hydrogen bonds are formed, and the salt ions bond with O. As a result, it is more difficulty for water molecules to bond and form ice. C. Hydrogen bonds are broken, and the salt ions bond with O and H respectively. As a result, it is more difficult for water molecules to bond and form ice.
Outline at least 3 ecological roles of marine flowering plants
What will be an ideal response?
The hospital where you work is having an emergency blood shortage. Select the following blood types that could safely be given to a young female with type AB Rh- blood.
_____ A Rh- blood _____ A Rh+ blood _____ AB Rh- blood _____ AB Rh+ blood _____ B Rh- blood _____ B Rh+ blood _____ O Rh- blood _____ O Rh+ blood Clarify Question What is the key concept addressed by the question? What type of thinking is required? Gather Content What do you already know about blood typing? What other information is related to the question? Choose Answer Given what you now know, what information is most likely to produce the correct answer? Reflect on Process Did your problem-solving process lead you to the correct answer? If not, where did the process break down or lead you astray? How can you revise your approach to produce a more desirable result?
The table below lists several genotypes associated with the lac operon in E. coli. For each, indicate with a "+" or a "-" whether functional ?-galactosidase would be expected to be produced at induced levels
?-Galactosidase Production Genotype No Lactose With Lactose (a) I + O+ Z+/F' I - O+ Z+ (b) I - Oc Z+/F' I - O+ Z- (c) I s Oc Z+/F' I + O+ Z+ (d) I - O+ Z+/F' I - O+ Z+ I + = wild-type repressor I - = mutant repressor (unable to bind to the operator) I s = mutant repressor (insensitive to lactose) O+ = wild-type operator Oc = constitutive operator (insensitive to repressor)