Solve the problem.The motion of a projectile that is fired at a 45° angle with the horizontal is given by x = v0
t, 
for t in 
Suppose a projectile is fired with an initial velocity of 200 feet per second at an angle of 45° with the horizontal. Find (a) the time when it reaches maximum altitude (b) the maximum altitude.
A. (a) 17.7 sec
(b) 625 ft
B. (a) 4.4 sec
(b) 313 ft
C. (a) 8.8 sec
(b) 1250 ft
D. (a) 8.8 sec
(b) 313 ft
Answer: B
Mathematics
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