Consider the difference equation xk+1 = Axk, where A has eigenvalues and corresponding eigenvectors v1, v2, and v3 given below. Find the general solution of this difference equation if x0 is given as below.?1 = 1.3, ?2 = 0.8, ?3 = 0.6, v1 =
, v2 =
, v3 =
, and 
A. xk = (1.3)kv1 + (0.8)kv2 + (0.6)kv3
B. xk = 5(1.3)kv1 - 3(0.8)kv2 + 3(0.6)kv3
C. xk = (1.3)kv1 - 3(0.8)kv2 + 3(0.6)kv3
D. xk = 5(1.3)kv1 - 3(0.8)kv2 + (0.6)kv3
Answer: B
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