Solve.The monthly cost of a certain long distance service is given by the formula 
where C is in dollars and t is the amount of time in minutes called in a month. Find the cost of calling long distance for 110 minutes in a month.
A. $17.65
B. $7.70
C. $20.95
D. $16.65
Answer: A
You might also like to view...
Solve using factoring.If tickets are sold for $20, it is estimated that 50 tickets will be sold. For each one-dollar reduction in the ticket price, there will be an additional 5 tickets sold. The revenue from ticket sales when the ticket prices are reduced by x dollars is given by (20 - x)(50 + 5x). Determine the ticket price that will result in ticket sales of $1105.
A. 13 dollars or 17 dollars B. 13 dollars or 18 dollars C. 27 dollars or 3 dollars D. 14 dollars or 17 dollars
Solve the problem.A retailer knows that n games can be sold in a month at a price given by P(n) = 
, in dollars per game. Assume that he buys each game for 
and sells every one that he buys. If he wishes to make a profit of at least 
per month on sales of this game, how many games must he sell each month?
A. 20 ? n ? 50 B. 20 ? n ? 30 C. 0 ? n ? 20 D. 15 ? n ? 25
Solve the inequality.m3 - 36m ? 0
A. [-6, 0] or [6, ?) B. (-6, 0) or (6, ?) C. (-6, 0] or [6, ?) D. [-6, 0) or (6, ?)
Solve the linear equation.-40 - 2(3z - 2) = 3z - 3(4 - z)
A. -4 B. 2 C. 1 D. -2