(a) F 5 = 3000(F/A,10%,4) = 3000(4.6410) = $13,923 (b) F 4 = 3000[(F/A,10%,3) + (P/F,10%,1)] = 3000[3.3100 + 0.9091] = $12,657





What will be an ideal response?


First find P in year 0 and then move to year 9
P = 200 + 200(P/A,10%,3) + 300(P/A,10%,3)(P/F,10%,3)
= 200 + 200(2.4869) + 300(2.4869)(0.7513)
= $1257.90
F = 1257.90(F/P,10%,9)
= 1257.90(2.3579)
= $2966

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