Solve the initial value problem.Differential Equation:   =  (t + 2)5/2i + etjInitial Condition:  r(0) = 0

A. r(t) = [(t + 2)7/2 - 27/2]i + (et - 1)j
B. r(t) = [(t + 2)9/2 - 29/2]i + (et - 1)j
C. r(t) = [(t + 2)7/2 + 27/2]i + (et + 1)j
D. r(t) = (t + 2)7/2i + etj


Answer: A

Mathematics

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