When using EUI-64, what is the correct result of inverting the seventh bit of the interface ID with an interface ID of B2C3:7AA0:8801?
A) B2C3:7A80:8801
B) B0C3:7AA0:8801
C) B3C3:7AA0:8801
D) BDC3:7AA0:8801
B
Explanation: B) Only the seventh bit is affected, so the hex digit 2 (0010 in binary) becomes 0 (0000 in binary), making the full interface ID 0348:45FF:798A because the rest is unaffected.
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