Solve the problem.Over a portion of a battery's charge, the voltage delivered drops as the battery is discharged, according to the following equation:V(t) = 1.5 - 0.06 ln (1 + 0.1t)
where t is the time in hours that the battery is being discharged. Use the second-degree Taylor polynomial for V(t) to find the average voltage over the first 5 hours.
A. p2(t) = 1.5 - 0.006t + 0.0006t2; 1.49 volts
B. p2(t) = 1.5 - 0.006t + 0.0003t2; 1.4875 volts
C. p2(t) = 1.5 - 0.006t + 0.0003t2; 1.4775 volts
D. p2(t) = 1.5 - 0.006t + 0.0006t2; 1.485 volts
Answer: B
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