A couple is planning to have four children. Suppose that for this couple the probability of a boy is 46% and the probability of a girl is 54%. (Assume the gender of each child is independent from that of the other children.)What is the probability that they will have one girl and three boys?
A.
B. 0.463 × 0.54
C. 0.54 + 0.46 + 0.46 + 0.46
D. 4 × 0.463 × 0.54
E. none of these
Answer: D
You might also like to view...
Solve the equation for y in terms of x.ln y + 2 ln x = 1 + ln 9
A. y = 10 - 2x
B. y = e + 9 - 2x
C. y =
D. y =
Solve the problem.A musician plans to perform 6 selections. In how many ways can she arrange the musical selections?
A. 72 B. 360 C. 36 D. 720
Provide an appropriate response.Solving for which variable in which equation involves the least amount of work?x + 6y = 0x - 6y = 24
A. x in equation 2 B. y in equation 2 C. y in equation 1 D. x in equation 1
Write the sample space for the given experiment.A box contains 10 red cards numbered 1 through 10. One card is drawn at random and its number is recorded.
A. {100} B. {10} C. {1, 2, 3, 4, 5, 6, 7, 8, 9, 10} D. {1, 10}