State the dual problem. Use y1, y2,  y3 and y4 as the variables. Given: y1 ? 0, y2 ? 0,  y3 ? 0, and y4Minimizew = 2x1 + 3x2 + x3subject to:x1 + 3x2 + 2x3 ? 39 2x1 + 4x2 + 3x3 ? 52 x1 ? 0, x2 ? 0, x3 ? 0

A. Maximize z = 52y1 + 39y2

subject to:2y1 + y2 ? 2
 4y1 + 3y2 ? 3
 3y1 + 2y2 ? 1
B. Maximize z = 52y1 + 39y2
subject to:2y1 + y2 ? 2
 4y1 + 3y2 ? 3
 3y1 + 2y2 ? 1
C.
Maximizez = 39y1 + 52y2
subject to:y1 + 2y2 ? 2
 3y1 + 4y2 ? 3
 2y1 + 3y2 ? 1
D.
Maximizez = 39y1 + 52y2
subject to:y1 + 2y2 ? 2
 3y1 + 4y2 ? 3
 2y1 + 3y2 ? 1


Answer: D

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