State the dual problem. Use y1, y2, y3 and y4 as the variables. Given: y1 ? 0, y2 ? 0, y3 ? 0, and y4
Minimizew = 2x1 + 3x2 + x3subject to:x1 + 3x2 + 2x3 ? 39 2x1 + 4x2 + 3x3 ? 52 x1 ? 0, x2 ? 0, x3 ? 0
A. Maximize z = 52y1 + 39y2
| subject to: | 2y1 + y2 ? 2 |
3y1 + 2y2 ? 1
B. Maximize z = 52y1 + 39y2
| subject to: | 2y1 + y2 ? 2 |
3y1 + 2y2 ? 1
C.
| Maximize | z = 39y1 + 52y2 |
| subject to: | y1 + 2y2 ? 2 |
2y1 + 3y2 ? 1
D.
| Maximize | z = 39y1 + 52y2 |
| subject to: | y1 + 2y2 ? 2 |
2y1 + 3y2 ? 1
Answer: D
Mathematics
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