Find the equation of the tangent line to the equation at the point where x has the given value.y = (2x2 + 3x + 4)(2x - 3); x = 0

A. y = - 1x + 12
B. y = -1x - 12
C. y = - 1x - 12
D. y = -1x + 12


Answer: B

Mathematics

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