Solve the initial value problem.Differential Equation: 
= (12t2 - 5)i - j + 
kInitial Condition: r(0) = -5i + 3j + 11k
A. r(t) = (4t3 + 5t + 5)i + (3 + t)j + (
+ 9)k
B. r(t) = (4t3 - 5t - 5)i + (3 - t)j + (
- 9)k
C. r(t) = (12t3 - 5t - 5)i + (3 - t)j + (
+ 9)k
D. r(t) = (4t3 - 5t - 5)i + (3 - t)j + (2
+ 9)k
Answer: D
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