Solve the initial value problem for x as a function of t.(t + 1) 
= x2 + 1 , t > -1 , x(3) = tan 1
A. x = tan [ ln
- ln 4]
B. x = 
- 
C. x = tan-1 [ ln
- ln 4 + 1]
D. x = tan [ ln
- ln 4 + 1]
Answer: D
Mathematics
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