Solve the initial value problem. = 1; y "(0) = -4, y '(0) = 5, y(0) = 5

A. y = x3 - 2x2 + 5x + 5
B. y = x3 + 2x2 + 5
C. y = x3 - 2x2 + 5x + 5
D. y = 5


Answer: C

Mathematics

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A.

B.

C.

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A.

B.

C.

D.

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