An object moves in simple harmonic motion described by the given equation, where t is measured in seconds and d in meters . Find the maximum displacement, the frequency, and the time required for one cycle.d = 4 + 3 cos 5?t meters
A. displacement = 7 meters; period = 
seconds; f = 
oscillations/second
B. displacement = 3 meters; period = 
seconds; f = 
oscillations/second
C. displacement = 7 meters; period = 
? seconds; f = 
oscillations/second
D. displacement = 3 meters; period = 
seconds; f = 
oscillations/second
Answer: B
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Rewrite each number using scientific notation before performing the operation. Leave your answer in scientific notation form.3 × 10-35 + 5 × 10-34
A. 5.3 × 10-33 B. 8.0 × 10-34 C. 5.3 × 10-34 D. 5.3 × 10-35
Simplify the expression.[-(-4y2 - 2y + 7y3) - (10y2 + 10y - 9y3)] - y2
A. -16y3 + 13y2 + 12 B. 2y3 - 5y2 - 8 C. 2y3 - 7y2 - 8y D. 16y3 - 15y2 - 12
Solve.-3 logt 64 = -9
A. -12 B. 12 C. 3 D. 4
Solve the equation and check your solution.
- 
= 
A. 54
B. 
C. -18
D. 18