Solve the problem.A baseball pitcher throws a baseball with an initial speed of 128 feet per second at an angle of 20° to the horizontal. The ball leaves the pitcher's hand at a height of 4 feet. Find parametric equations that describe the motion of the ball as a function of time. How long is the ball in the air? When is the ball at its maximum height? What is the maximum height of the ball?
A. x = 120.28t, y = -16t2 + 43.78t + 4
5.65 sec, 1.368 sec,
29.948 feet
B. x = 120.28t, y = -16t2 + 43.78t + 4
2.642 sec, 1.368 sec,
3.984 feet
C. x = 120.28t, y = -16t2 + 43.78t + 4
5.283 sec, 1.368 sec,
243.586 feet
D. x = 120.28t, y = -16t2 + 43.78t + 4
2.825 sec, 1.368 sec,
33.948 feet
Answer: D
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A. 25 inches B. 22 inches C. 26 inches D. 27 inches
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Simplify.
- (13 + 
)
A. 25
B. 
C. 
D. 3
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