Solve. Assume the exercise describes a linear relationship.An investment is worth $3592 in 2006. By 2010 it has grown to $4084. Let y be the value of the investment in the year x, where x = 0 represents 2006. Write a linear equation that models the value of the investment in the year x.
A. y = 123x + 3592
B. y = -123x + 4576
C. y = x + 3592
D. y = -123x + 3592
Answer: A
Mathematics
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