Graph the function over a one-period interval.y = 3cos 
A. 
B. 
C. 
D. 
Answer: B
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Insert parentheses, if needed, to make the expression on the left equal to the number on the right.200 ÷ 10 - 3 + 2 = 15
A. 200 ÷ 10 - (3 + 2) = 15 B. 200 ÷ (10 - 3) + 2 = 15 C. 200 ÷ 10 - 3 + 2 = 15 D. (200 ÷ 10) - 3 + 2 = 15
Solve the system by the substitution method. If there is no solution or an infinite number of solutions, so state. Use set notation to express the solution set.
A. {(1, 1)}
B. infinitely many solutions; {
y - 6x = 2} or {
5y = 30x + 10}
C. no solution; ?
D. {(-1.5, -1)}
Graph the quadratic function. Determine the vertex, find the equation of the axis of symmetry, find any x- and y-intercepts, and state the domain and range in interval notation.f(x) = -x2 + 2x
A. vertex: (1, 1)
axis of symmetry: x = 1
x-intercepts: 0 and 2; y-intercept: 0
domain: (-?, ?); range: (-?, 1]
B. vertex: (-1, 1)
axis of symmetry: x = -1
x-intercepts: 0 and - 2; y-intercept: 0
domain: (-?, ?); range: (-?, 1]
C. vertex: (1, -1)
axis of symmetry: x = 1
x-intercept: none; y-intercept: -2
domain: (-?, ?); range: (-?, -1]
D. vertex: (-1, -1)
axis of symmetry: x = -1
x-intercept: none; y-intercept: -2
domain: (-?, ?); range: (-?, -1]
Compute r''(t).r(t) = (2 ln(5t))i + (7t3)j
A. r''(t) = 
t-2i + 42tj
B. r''(t) = - 
i + 42tj
C. r''(t) = 
i + 21tj
D. r''(t)= - 
t-2i + 42tj