Use the given table for y = ax2 + bx + c to solve ax2 + bx + c < 0 or ax2 + bx + c > 0, as indicated.y = x2 - 16; ax2 + bx + c < 0

A. -5 < x < 5
B. x < -5 or x > 5
C. -4 < x < 4
D. x < -4 or x > 4


Answer: C

Mathematics

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Mathematics

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Mathematics