The distance in the x direction between two control points on a vertical aerial photograph is 6.2". If the distance between these same two points is 4.9" on another photograph having a scale of 1:24,000, determine the scale of the first vertical aerial photograph. If the focal length of the camera is 6"and the average elevation at these points is 300 ft, determine the flying height from which each photograph was taken.

What will be an ideal response?




Let the actual distance between the points MN be x feet

M'N' = 4.9 in = 0.40833 ft

(M'N') / (MN) = (ON') / (ON) = Scale 1:24,000

1 / 24000 = 0.0.40833 / x

x = 9800 feet

Now solve for the scale of the second photo.

M'N = 6.2 in = 0.5167 ft

Scale = 0.5167 / 9800

Scale = 1:18,970

Now determine the height from which the first photo was

taken (H1).

1 / 18,970 = (6.0/12) / (H1 – 300)

H1 = 9,784 feet

Now determine the height from which the second photo was taken (H2).

1 / 24,000 = (6.0/12) / (H2 – 300)

H2 = 12,300 feet

Therefore, the scale of the first photograph is 1:18,970, the elevation it was taken

from is 9,784 feet, and the second photograph was taken at an elevation of 12,300

feet.

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