2.75 kg of air is initially at 800°C. The internal energy of the air is reduced by 525 kJ in a cooling process. Considering the variability of the specific heats, determine the final temperature of the air.
Given: m = 2.75 kg; T1 = 800°C =1073 K; ?U = -525 kJ
What will be an ideal response?
At T1, u1 = 821.84 kJ/kg
?U = m (u2 – u1)
Solving for u2 = 821.84 + (-525 kJ)/(2.75 kg) = 630.93 kJ/kg
Interpolating, this corresponds to T2 = 847 K = 574°C
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