Find the exact value of the expression.
A. - 
B. - 
C. -2
D. -
Answer: D
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Solve the problem.The distance D in feet that an object has fallen after t seconds is given by D(t) = 16t2. (i) Evaluate D(2) and D(5). (ii) Calculate the slope of the secant line through D(2) and D(5) on the graph of D and interpret the answer in terms of an average rate of change of D from 2 to 5.
A. (i) 32, 80 (ii) 112; the object's average speed from 2 to 5 seconds is 112 ft/sec. B. (i) 64, 400 (ii) 48; the object's average speed from 2 to 5 seconds is 48 ft/sec. C. (i) 32, 80 (ii) 48; the object's average speed from 2 to 5 seconds is 48 ft/sec. D. (i) 64, 400 (ii) 112; the object's average speed from 2 to 5 seconds is 112 ft/sec.
Solve the problem.At a local grocery store the demand for ground beef is approximately 50 pounds per week when the price per pound is $4, but is only 40 pounds per week when the price rises to $5.50 per pound. Assuming a linear relationship between the demand x and the price per pound p, express the price as a function of demand. Use this model to predict the demand if the price rises to $5.80 per pound.
A. p = 0.15x + 11.5; 38 pounds B. p = 11.5x + -0.15; 40 pounds C. p = - 0.15x + 11.5; 38 pounds D. p = - 0.15x - 11.5; 40 pounds
Graph the circle.x2 + y2 - 2x - 10y + 1 = 0
A. 
B. 
C. 
D. 
Add.23 + 5 + (-24)
A. -6 B. 4 C. 42 D. 52