Find the output voltage of the peak detector shown in Figure P9.66. Use sinusoidal input voltages with amplitude 6, 1.5, and 0.4 V. Let V? = 0.7 V.
Analysis:
The capacitor will charge to .
6 V:
Therefore, the input sine wave will be shifted up 5.3 V to produce the output. As a result, after the cycle (the capacitor builds up its stored charge during the third quarter cycle), the average value of the output will be 5.3 V.
1.5 V:
Therefore, the input sine wave will be shifted up 0.8 V to produce the output. As a result, after the cycle (the capacitor builds up its stored charge during the third quarter cycle), the average value of the output will be 0.8 V.
0.4 V:
Since the input is less than 0.7 V, the capacitor does not charge and the output voltage is 0 V.
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