Solve for the indicated variable.d = rt for r
A. r = dt
B. r = 
C. r = d - t
D. r = 
Answer: D
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Find the equation of the tangent line to the equation at the point where x has the given value.y = (2x2 + 3x + 4)(2x - 3); x = 0
A. y = - 1x + 12 B. y = -1x - 12 C. y = - 1x - 12 D. y = -1x + 12
You want a linearization that will replace the function over an interval that includes the point x0. To make your subsequent work as simple as possible, you want to center the linearization not at x0 but at a nearby integer x = a at which the function and its derivative are easy to evaluate. What linearization do you use?f(x) = -2x2 - 5x + 9, x0 = 1.1
A. -11 - 9x B. 12 - 10x C. 2 D. 11 - 9x
Express the number as the ratio of two integers.0.386386 . . .
A. 
B. 
C. 
D. 
Graph the equation.g(x) = -x2 - 2x - 6
A. 
B. 
C. 
D. 