Find the area of the region.
9 mi
A. 77 sq mi
B. 81 sq mi
C. 84 sq mi
D. 36 sq mi
Answer: B
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Evaluate the expression for the given value or values.-xy for x = 9, y = 73
A. -657 B. 657 C. 642 D. -642
Convert using dimensional analysis.67 years to minutes (assume 365.25 days in a year)
A. 96,480 min. B. 35,239,320 min. C. 35,215,200 min. D. 19,296 min.
Solve the problem.Peter's Construction Company needs to cut an arch for the top of a doorway. The arch needs to be 14 feet wide and 4 feet high. The arch will be a section of a circle, drawn using a stretched string with a pencil attached at the end as a compass. Using the coordinate system as shown in the drawing, find the coordinates of the point that would be the center of the circle. Also find the radius of the circle. Round to the hundredths place.
?a = 7
A. (0, -3.79); 7.79 B. (0, -3.88); 7.88 C. (0, -41.25); 45.25 D. (0, -4.13); 8.13
Use the frequency distribution to find the mean and the sample standard deviation. Does the data form a normal distribution? Remember: if the data fall within 2% of the empirical rule of 68%, 95%, and 99.7% for one, two, or three standard deviations, respectively, they form a normal distribution.
Weight (lb) Midpointx Frequency f1.5 - 10.5 1210.5 - 19.5 3919.5 - 28.5 12028.5 - 37.5 20737.5 - 46.5 36846.5 - 55.5 34455.5 - 64.5 22264.5 - 73.5 10073.5 - 82.5 3082.5 - 91.5 12 A. The mean is 36 lb. The sample standard deviation is 10.4 lb. The data forms a normal distribution. B. The mean is 36 lb. The sample standard deviation is 10.4 lb. The data doesn't form a normal distribution. C. The mean is 46 lb. The sample standard deviation is 14.6 lb. The data doesn't form a normal distribution. D. The mean is 38 lb. The sample standard deviation is 13.6 lb. The data doesn't form a normal distribution. E. The mean is 46 lb. The sample standard deviation is 14.6 lb. The data forms a normal distribution.