Find the slope of a line tangent to the given curve at the point P by finding the limit of the slopes of the secant lines PQ as Q approaches P.y = x3 - 4x; P is (-4, -48); let Q have x-values of -3.5, -3.9, -3.99, -3.999
A. Slopes: 6.25, 10.81, 11.8801, 11.988001
m = 12
B. Slopes: 38.25, 42.81, 43.8801, 43.988001
m = 44
C. Slopes: 22.25, 26.81, 27.8801, 27.988001
m = 28
D. Slopes: 42.25, 46.81, 47.8801, 47.988001
m = 48
Answer: B
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