State the dual problem. Use y1, y2, and y3 as the variables. Given: y1 ? 0, y2 ? 0, and y3
Minimizew = 6x1 + 3x2subject to:3x1 + 2x2 ? 22 2x1 + 5x2 ? 38 x1 ? 0, x2 ? 0
A.
| Maximize | z = 22y1 + 38y2 |
| subject to: | 3y1 + 2y2 ? 6 |
B.
| Maximize | z = 22y1 + 38y2 |
| subject to: | 3y1 + 2y2 ? 6 |
C.
| Maximize | z = 38y1 + 22y2 |
| subject to: | 2y1 + 3y2 ? 6 |
D.
| Maximize | z = 38y1 + 22y2 |
| subject to: | 2y1 + 3y2 ? 6 |
Answer: B
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