A couple wishes to determine the chances of having a blue-eyed baby. Both parents have brown eyes, but have heterozygous gene pairs for eye color. Calculate the odds of their having a child with blue eyes
A.
10%
B.
20%
C.
25%
D.
50%
ANS: C
Each parent has a heterozygous gene pair for brown eyes, which means that each parent has one blue gene and one brown gene. Using a Punnett square, one can calculate the odds of their having a blue-eyed baby to be 25%.
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