Assuming a normal distribution, where would you find approximately two thirds of the scores if they ranged from 30 to 68, M = 45, and SD = 7? Between:
a. 30 and 68
b. 31 and 59
c. 37 and 61
d. 38 and 52
ANS: D
In the normal curve, 68% of scores will be within one standard deviation above or below the mean. In the example, two thirds of scores (66%) fall between 30 and 68. The mean = 45 and the SD = 7 for this sample. It follows that scores will fall between one standard deviation below (45 – 7 = 38) and one standard deviation above the mean (45 + 7 = 52).
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