Two neighboring Caribbean islands harbor iguana populations. One island (island
A) has a total iguana population of 800, while the other (island B) has a population less than half that size, numbering 250. On island A, the frequency of an allele p is estimated at 0.75, while this same allele is present at a frequency of 0.90 on island B. During a hurricane tracking across the islands, a group of about 100 iguanas get rafted from island A to island B. What effect does this have on the frequency of allele p on island B?
The migrant subpopulation is 100/800, or 0.125. This can be taken as m, the migration coefficient. The frequency of p in island A is 0.75; call this pA. pB is given as 0.9. Using the relationship ?p = m(pA - pB), ?p = 0.125(0.75 - 0.9 ) = 0.125(-0.15 ) = -0.019. The frequency of p on island B thus declines by 0.019, to 0.9 - 0.019 = 0.881.
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