Solve the equation. Round to the nearest tenth, if necessary.If an object is thrown upward from the ground with an initial velocity of 48 ft/sec, its height after t seconds is given by h = 48t - 16t2. Find the maximum height attained by the object. (The object will attain maximum height exactly at the halfway point in terms of the time t, where t = 0 is at the beginning of the object's flight, and the final time is when the object hits the ground.)
A. 20 ft
B. 32 ft
C. 36 ft
D. 48 ft
Answer: C
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The hyperbola shown in the calculator-generated graph was graphed in function mode with a square viewing window. What are the two functions y1 and y2 that were used to obtain the graph whose equation is given?10
-10
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