The number of daughter chromosomes in a human cell (diploid number 46) in anaphase II of meiosis is
a. 2.
b. 23.
c. 46.
d. 69.
e. 92.
Answer: c. 46.
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The table shows the distribution of traits (A-E) in six extant species (1-6). A "0" indicates the ancestral condition, and a "1" indicates the derived condition. Which pair of species shares the greatest number of derived characters (synapomorphies)?
A. 4 and 5
B. 2 and 4
C. 1 and 4
D. 3 and 4
E. 2 and 5
Clarify Question
· What is the key concept addressed by the question?
· What type of thinking is required?
· What key words does the question contain and what do they mean?
Gather Content
· What do you already know about cladistics?
Consider Possibilities
· What other information is related to the question? Which information is most useful?
Choose Answer
· Given what you now know, what information and/or problem solving approach is most likely to produce the correct answer?
Reflect on Process · Did your problem-solving process lead you to the correct answer? If not, where did the process break down or lead you astray? How can you revise your approach to produce a more desirable result?
The choanoflagellates are in the supergroup
A. Opisthokonta B. Rhizaria C. Amoebozoa D. Stramenopila E. Alveolata
Which of the following is TRUE of fate mapping?
A. It determines the ultimate structure/function of a particular cell type during embryonic development. B. It maps the genes of an embryo. C. It assesses the quality of a developing embryo. D. It maps the proteins within a morphogenic field. E. It determines hereditable disorders in the embryo.
If you could remove all the phosphate in the cell, what would happen to the ATP cycle?
A. It would cycle faster because the lack of phosphate would drive the cycle. B. It would stop when all the ADP had been converted into ATP. C. It would not affect the ATP cycle. D. It would stop when all the ATP had been converted into ADP. E. It would cycle faster because of the buildup of ATP.