Solve the problem.An investment is worth $3475 in 2010. By 2013 it has grown to $4948. Let y be the value of the investment in the year x, where x = 0 represents 2010. Write a linear equation that models the value of the investment in the year x.

A. y = -491x + 3475
B. y = -491x + 6421
C. y = 491x + 3475
D. y = x + 3475


Answer: C

Mathematics

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