Solve the problem.An investment is worth $3475 in 2010. By 2013 it has grown to $4948. Let y be the value of the investment in the year x, where x = 0 represents 2010. Write a linear equation that models the value of the investment in the year x.
A. y = -491x + 3475
B. y = -491x + 6421
C. y = 491x + 3475
D. y = x + 3475
Answer: C
Mathematics
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B. x ? n?
C. (-?, ?)
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A.
B.
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D.
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Solve by the method specified.Addition method8x + 5y = -704x - 3y = -2
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Mathematics