Determine the amount of rebar needed for the foundation walls shown in Figures 11.38 and 11.39. Allow for two inches of cover. Add 10 percent for lap and waste to the continuous bars.
What will be an ideal response?
From Problem 42, the length of the wall is 165?. The vertical bars are calculated as follows:
Number of spaces = 165? / 1? = 165 spaces
Add 1 to get the number of vertical bars – Use 166 bars per side
The vertical bars are 11?10? long (12? – 2?).
Total length of vertical bars (lf) = 2 sides × 166 bars per side × 11?10? per bar = 3,929 lf
Total weight of vertical bars (pounds) = 3,929 lf × 0.668 pounds per lf = 2,625 pounds
The horizontal bars are calculated as follows:
Number of spaces = 12? / 1? = 12 spaces
Add 1 to get the number of horizontal bars that are needed to meet the spacing requirements for one side – Use 13 bars per side
Total length of horizontal bars (lf) = 165? × 13 bars per side × 2 sides = 4,290 lf
Total weight of horizontal bars (pounds) = 4,290 lf × 0.668 pounds per lf = 2,866 pounds
Add for waste and lap.
Total weight of horizontal bars (pounds) = 2,866 pounds × 1.10 = 3,153 pounds
Total weight of rebar (pounds) = 2,625 pounds + 3,153 pounds = 5,778 pounds
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