Translate the following problem statements into equations. Then solve the equations to find the requested result.
Find three consecutive integers in which the sum of the first two is 27 more than the third.
Let
Let smallest number = n
Three consecutive numbers are: n, (n + 1), and (n + 2)
Equation: n + (n + 1) = 27 + (n + 2)
Solve for n: 2n + 1 = 29 + n
2n — n = 29 —1 n =28
Solution: The three numbers are: 28, 29, and 30.
Check: 28+ 29=27+ 30
57 = 57
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