Non-static function members of a class gain access to the calling object’s members by
a) a pointer to the calling object that is implicitly provided by the compiler. The
name of this pointer is this. Members are prefixed implicitly by this->, as
in```
this->>membername
```
b) a variable called self that is an alias for the calling object. This self is used
to access the members of the object.
c) There is no particular mechanism, the variables just know what the calling object
is and automatically refer to the calling object.
d) None of the above.
a) a pointer to the calling object that is implicitly provided by the compiler. The
name of this pointer is this. Members are prefixed implicitly by this->, as
in```
this->>membername
```
You might also like to view...
Experiment with the Hello CGI example presesnted in Figures 9.10 and Figure 9.11.
a. Obtain the source files for the Hello CGI example presesnted in Figures 9.10 and Figure 9.11. b. Install hello.html on the web server: be sure to open its access to world-readable. c. Compile hello.c (with util.c for the query-string processing routines) to generate an executable Hello.cgi. (The command is%gcc hello.c util.c -o hello.cgi). Install hello.cgi on the web server: be sure to open its access to world-readable and world-executable. d. Open a browser and specify the URL for hello.html. When the page is displayed, press the button to submit the form and invoke hello.cgi. e. Summarize the experiment and report the result.
Suppose the following code is embedded in an otherwise correct and complete program. Answer below the question about what version of f() is called in g().
``` void f(); //global namespace A { void g() { f(); //Does this call A::f()? Or the global f()? } void f(); } ``` a) The call is to the global f(); b) The call is to the namespace A version of f(), i.e., A::f(); c) There is an error. There is a conflict between the namespace f() and the global f(), so there is no call made at all d) There are other errors that prevent the code from running.
Given the following schema:
Student(Id,Name) Transcript(StudId,CourseName,Semester,Grade)Formulate the following query in SQL: Create a list of all students (Id, Name) and, for each student, list the average grade for the courses taken in the S2002 semester. Note that there can be students who did not take any courses in S2002. For these, the average grade should be listed as 0.
One of Mark's designers tells Mark that she will help him out and recreate the graphic above with a simple rainbow radial gradient. Is her method the best she could use?
What will be an ideal response?