Air is contained in a 2-m3 volume at 200ºC and 20 MPa. The mass of the air is nearest:
A) 310 kg
B) 295 kg
C) 280 kg
D) 265 kg
C) 280 kg
The high pressure suggests that real-gas effects will be significant. Van de Waals equation is
where we have used the units on a as kPa?m6/kg2 so that kPa can be used for pressure and kJ in the units for R. This requires a trial-and-error solution. As an approximation, the ideal gas law provides v = RT / P = 0.287 × 473 / 20 000 = 0.00679 m3 /kg. The solution follows:
Or, using Fig. H-2 in the Appendix, with v = ZRT / P,
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Fill in the blank(s) with the appropriate word(s).
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Fill in the blank(s) with the appropriate word(s).
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Explain who should be involved in the risk assessment process and why.
What will be an ideal response?