Imagine a downhill race between four objects each of mass M. One object such as a skier (P) is best modeled as a particle (shown as a small flat object) translating down the hill. The other objects are modeled as a solid cylinder (C), hoop (H) and a solid sphere (S) each of radius R rolling down the hill without slipping. All four objects start from rest a t a height h. Assuming mechanical energy losses due to friction may be ignored, determine the order in which the objects cross the finish line. Use their letter designation: P, C, H and S and arrange them from first to last to arrive at the finish line.
Answer: From the energy conservation
1/2mv^2+1/2Iw^2 = mgh
here I = moment of inertia = cmr^2
w = v/r
1/2mv^2+1/2cmr^2*w^2 = mgh
v = sqrt(2gh/1+c)
c is a constant
for particle c = 1
vp = sqrt(2gh/1+1) = sqrt(2gh/2)
for cylinder
vc = sqrt(2gh/1+1/2) = sqrt(4gh/3)
for hoop
vh = sqrt(2gh/1+1) = sqrt(2gh/2)
for solid sphere
vs = sqrt(2gh/1+2/5) = sqrt(10gh/7)
vs>vc>vh=vp
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