Question

1. Semantics are the set of grammar rules for a high-level language.
2. The CPU refers to the control unit and the ALU.(arithmetic logic unit)
3. A modern digital computer represents values in memory in base 10.
4. A compiler is hardware used to translate a C++ program into machine language.
5. The source file is the machine language version of a C++ program.

Answer 1

1. false
2. true
3. false
4. false
5. false

Answer 2

(10 * 10) * (10 * 10 * 10) = 

Answer 3

=(3*7)1(2*3*5)
= 7 (2 * 5)
='7/10

Answer 4

value_other_than_100

Answer 5


Answer 6

p = 4s = 4 * 2 =8
Perimeter = 8 inches

Answer 7

Volume of cone ^ 37.70  (rounded to 2 places)

Answer 8

A. Extract a value from the input stream and assign it to a variable

Answer 9

C. Global

Answer 10

miles/hour    feet/second, furlongs/fortnight

Answer 11


Answer 12

Data List:    "Impala", 15, "Camaro", 12, "Corvette", 5

Answer 13


Answer 14

2x + 1 - 1 -x+ 2 - 1    Added --1 to both sides
2x -x=x-x+1    Added -x to both sides
x=1    This is the solution.

Answer 15


Answer 16

```
produce report
CALL initial processing
DO WHILE name < > "End of Data" CALL detail_processing
LOOP
CALL final_processing
initial_processing
LET count = 0
INPUT name, sex_code, status_code
detail_processing
IF sex code = "F" AND status_code = "F" 111LN OUTPUT name
LET count = count + I
END IF
INPUT name, sex_code, status_code
final_processing
OUTPUT "total number of students reported is ", count
```

Answer 17

Reciprocal factors
2.2 (lb / kg)    1/2.2 (kg / lb)
10 ($ / kg)    1/10 (kg / $)
Multiply factors
x ($ I purchase) = 10 ($ / kg) * I / 2.2 (kg / lb) * 3 (lb / purchase)
Multiply factors
x ($ / purchase) = 13.64 ($ / purchase) Cost of purchase of 3 lbs is $13.64.

Answer 18

4, 1,
3, 1,
2, 1,
4, 2,
3, 2,
2, 2,
4, 3,
3, 3,
2, 3,

Answer 19

Initialization is needed when a variable in an expression about to be evaluated has not yet been assigned a value. This must be done for variables in conditional expressions (in IF and LOOP statements) as well as for variables in arithmetic expressions. This includes all variables on the right of the equal sign in a LET statement.
Initialization is not needed when a value in an expression has been previously assigned by:
A LET statement (for example by a calculation)
An INPUT statement.
Remember, variables on the left of the equal sign in a LET statement do not need to be initialized before hand. In fact this is how they get initialized.

Answer 20

```
LET count = 0
INPUT num
LET max = num
DO UNTIL num = 9999
IF num > max THEN LET max = num
LET count = count + 1
INPUT num
LOOP
IF count > 0 THEN
OUTPUT "The maximum value in the data list is ", max
ELSE
OUTPUT "The data list is empty."
END IF
```
Note: Choosing the initial value of the variable max must be done carefully. An initial value of zero would prevent finding the maximum of a list of numbers all less than zero. The best choice for the initial value is the first data item, the one read by the priming read.

Answer 21

1. True
2. False
3. False
4. True
5. False

Answer 22

First compute prices as decimal numbers: $29.375 and $25.125
The change is from $29.375 to $25.125, so:    v1= 29.375 and v2= 25.125
f = v2/vi    c = (f— 1) *100
f = 25.125 / 29.375 = 0.8553
c = (0.8553 — 1) * 100    c = 14.47% (decrease)
The current price of $258 is 14.47% less than the earlier $291 price.

Answer 23


Answer 24

Pair of reciprocal conversion factors:
0.6214 (mi / km)    1 / 0.6214 (km / mile)
x (km) = 10 ffii * 1 / 0.6214 (km / mi) = 16.09 km

Answer 25

Solution:    First part = 32 and    Second part = 48 — 32 =16
The two numbers are: 32 and 16.
Check:    32+ 16 = 48    Two parts combine to 48.
32 — 2(16) = 32    First part is twice second part

Answer 26

DEBBIE looked great in her BEADED BODICE as she entered the CAFE to get an ICED DECAF COFFEE.

Answer 27

OUTPUT "The average is "

Answer 28


Answer 29

(6/11) — (1/6)
= ((6 * 6) / (6 * 11) — ((1 * 11) (6 * 11))
= (36 / 66) — (11 / 66)
= 25/66    Lowest terms since there no common factors
25 / 66 —(5*5)/(6*11)

Answer 30

OUTPUT num1
OUTPUT num2
OUTPUT num3

Answer 31


Answer 32


Answer 33

(1) Problem Statement
(2) Input/Output Description
(3) Hand Calculations
(4) Algorithm Development
(5) Testing

Answer 34


Answer 35

1 to 6 significant digits (unclear)
Zeros may or may not be significant when there are no digits to the right of decimal point and the number ends in zeros.

Answer 36

Tip    x = (15 / 100) * $21.50    x = $3.23
Total 21.50 + 3.23 = $24.73

Answer 37

A. F(a) * F(b) is less than 0

Answer 38

```
c)    IF color_code < 1 THEN
OUTPUT "Invalid Code"
ELSE
IF color_code =1 THEN
OUTPUT "Red"
ELSE
IF color_code =2 THEN
OUTPUT "Blue"
ELSE
IF color_code = 3 THEN
OUTPUT "Yellow"
ELSE
OUTPUT "Invalid Code"
END IF
END IF
END IF
END IF
```

Answer 39


April sales were 20% less than March sales.

Answer 40

2y = 5 — 3x    Added —3x to both sides
y = (5 — 3x) / 2    Divided both sides by 2
y= 2(5 — 3x)    This is the solution.

Answer 41

S = 26 R = 3

Answer 42

Assign Values                  1 = 1 OR 1 = 2 OR 1 = 3
Add Parentheses            (1 = 1) OR (1 = 2) OR (1 = 3)
Do Arithmetic                 None needed
Evaluate Relational Exp.  T ORF OR F
Evaluate Logical Exp.      T OR F OR F
Left OR                           T OR F    =TORF   
Other OR Get                  = T
Result                             True

Answer 43


Total production of 14000 units is reached at 4:00 P.M.
Check by minutes per unit
Between 4:07 P.M. and 3:10 P.M. (57 minutes)
units grow by (14371 — 11240) or 3131 units. Thus, minutes per unit are 57 / 3131 = 0.01820 (min/unit)
14000 is 2760 units after 11240
Thus, time to produce 2760 units is:
0.01820 (min/unit)* 2760 (unit)
= 50.2 min = 50 min (rounded) = 50 minutes after 3:10 P.M.
Therefore, 14000 units are reached at 3:10 + 50 minutes = 4:00 P.M.

Answer 44

4 significant digits
Zeros that fall between non-zero digits are significant.

Answer 45

1
a = vb = i * 2 * 4 = 4
Area of triangle = 4 in2

Answer 46

```
LET n = n — 10
```

Answer 47

1 significant digit
If there is no whole part of the number, zeros immediately to the left of the decimal point are not significant.

Answer 48

Av sum / count = (22 + 33 + 47 + 16 + 12) / 5 = 130 / 5    =26

Answer 49

A. cstdlib

Answer 50


Answer 51

Assign Values                   1 <3 AND 1 > 0 AND 2 > = 1   
Add Parentheses              (1 < 3) AND (1 > 0) AND (2 > = 1)   
Do Arithmetic                    None needed   
Evaluate Relational Exp.         (T AND T) AND T   
Evaluate Logical Exp.           
Left AND first        T AND T AND T    = T AND T
Other AND        T AND T    =T
Get Result        True